How to use void pointer to generate 2D Array in c++

**Conraad** · 06-02-2010

Hello to all,
I recently start learning c++ language. I tried various method but I unable to generate a 2D array using void pointer. Can anyone tell me how to use void pointer to generate 2D Array in c++. Please help me.
I have tried following program to generate 2D Array, but it is not working properly.

Code:

int **k;
int rows = 2;
int cols = 2;

k = new int* [rows];
	
for(int x=0; x< rows; x++)
   k[x] = new int[cols];

for (int x = 0; x < rows; x++)
   for (int j = 0; y < cols; y++)
      k[x][y] = rand () % 10;

**absolute55** · 06-02-2010

Hey you have written wrong code for generating 2D Array in c++ using void pointer and that's why you are getting such type of problem. In your code you have written k = new int* instead of k = new void** and that's why you are getting such type of problem. I have written correct cod for you just try to understand it.

Code:


void*** k;
int rows = 2;
int cols = 2;

k = new void** [row];
	
for(int x=0; x< row; x++)
   k[x] = new void*[cols];

**Reegan** · 06-02-2010

It is very easy process to to generate 2D Array in c++ using void pointer. You have to just use two for loop to do this. I have written following program for you to generate 2D Array in c++. It is very simple program. In the following program I have create one pointer known as *q to generate 2D Array.

Code:

      int*q;
		 
		 
	for (int x = 0; x < rows; x++)
	{
		for (int y = 0; y < cols; y++)
		{
			q = new int;
			*q = rand () % 10;
			m[x][y] = q;
		}
	}

**opaper** · 06-02-2010

You can use void pointers to generate 2D Array in following ways. It is very simple program. You can declare pointer in following ways.

int *void; //it can be treated as any other type (char, float...)
void = new int[x];

Code:

int **void;
int X,Y;
cin >> X >> Y;

void = new int*[X];
for(int k=0;k

Above code will create a 2D array, with XxY dimentions.

**MindSpace** · 06-02-2010

Void pointer is treated as some unspecified type. It can be declare as normal pointer. It has same as size as other pointer. I have written following program for you. This program generate 2D Array using void pointer. It is very simple program. Just try to understand it.

Code:

int **k;

k = new int* [rows];     
for(int x=0; x< rows; x++)     
    k[x] = new int[cols];

for (int x = 0; x < rows; x++)
   for (int y = 0; y< cols; y++)
         k[x][y] = rand () % 10;

void ***v = (void ***)k;