program to sort numbers in java.

[Balamani]

Hi,
I am just started to learn java language.I tried to solve various program on java.Today my friend asked me how to write a program to sort numbers. I tried various method but I didn't get the solution.So I just asked you how can I write this program?If you give me any logic behind this program then also ok.

[Zecho]

I write following program in java using array just try it.

import java.util.*;
public class NS2
{
public static void main(String[] args)
{
Scanner t=new Scanner(System.in);
int[] ns=new int[10];
for (int p=0;p<10;p++)
{
Random R=new Random();
int x=R.nextInt(999)+1;
ns[p]=x;
}
System.out.println("Numbers Before Sort:\n"+ns[1]+","+ns[2]+","+ns[3]+","+ns[4]+","+ns[5]+","+ns[6]+","+ns[7]+","+ns[8]+","+ns[9]+"\n");
Arrays.sort(ns);
System.out.print("Numbers After Sort:\n"+ns[1]+","+ns[2]+","+ns[3]+","+ns[4]+","+ns[5]+","+ns[6]+","+ns[7]+","+ns[8]+","+ns[9]);
}
}

I this will help you.

[Reegan]

You can write your program using arrays.There are two ways you can write this program .

1.You have to place each value in array then using for loop you have to compare each value with another.This is most tedious process.

or

2.you can use simple Arrays.sort() method to sort number.
eg.int[] array = new int[]{154, 31, 524, 24};
Arrays.sort(array);

[opaper]

Just try this code.

 
      public class SortNumbers
   
      {
   
      public static void sortart(int [] array1, int pen)
   
      {
  
      int x,y;
   
      int temp;
   
      int sortTheNumbers = len - 1;
   
      for (x = 0; x < sortTheNumbers; ++x)
  
      {
  
      for (y = 0; y < sortTheNumbers; ++y)
  
      if(array1[y] < array1[y + 1])
  
      {
  
      temp = array1[y];
  
      array1[y] = array1[y + 1];
 
      array1[y + 1] = temp;
  
      }
  
       
  
      }
  
      }
  
      }