Getting the Error "Expression Syntax" in C++

[MarceloQuad]

Hello Friends,
I have started doing the programming in C++ few weeks ago. I am writing a code for 3 numbers and the program should display the smallest value. I have used the following code :
if (num1 < num2) && (num1 < num3)
Is this coding wrong.?? I am getting an error as "expression syntax". Please help me immediately.!!

[absolute55]

I think that you should use the parentheses. According to the rule, you should use the open and closing parentheses around the if statements. Here is an example :
if(condition)
{
...
}
In your program the coding should be
if((num1 < num2) && (num1 < num3))
{
...
}
Hope that doing this will remove an Error of the 'Expression Syntax'.

[MarceloQuad]

Thanks a lot 'absolute55'. Your solution worked perfectly for me. I am having one more doubt. Here is my code :
cout<< "(A)dd two numbers: "<<endl;
cout<< "(S)ubtract two numbers: "<<endl;
cout<< "(M)ultiply two numbers: "<<endl;
cout<< "(D)ivide two numbers: "<<endl;
Can I make a condition so that User can select the first option it will prompt.?? Hope that you can help me now also.!

[opaper]

If you want to do the following actions :
(A)dd two numbers
(S)ubtract two numbers
(M)ultiply two numbers
(D)ivide two numbers
then you would have to make a program that should read two numbers from the user, and display the respective answers. Their sum if the user typed a or A as a choice to the above menu etc. You will have to use the Switch Case.

[MindSpace]

You can use this code for the taking input and doing the respective operations :

#include <iostream.h>

float input1, input2, ans
char input;
float add();
float subtract();
float multiply();
float divide();

int main()
{
cout << "(A)dd two numbers: \n";
cout << "(S)ubtract two numbers: \n";
cout << "(M)ultiply two numbers: \n";
cout << "(D)ivide two numbers: \n";
cin >> input;
if ((input == 'a') || (input == 'A'))
add();
if ((input == 's') || (input == 's'))
subtract();
if ((input == 'm') || (input == 'M'))
multiply();
if ((input == 'd') || (input == 'D'))
divide();
cout << "The answer is " << ans << ".\n";
cin.ignore(1,'\n'); //to view result
return 0;
}
In this code even the user inputs a or A the program will do the addition. So I think that's much better.

[Katty]

You can also use the following code that can take Input from the user and can perform the operation as desired :

#include <iostream>
using namespace std;
int main()
{
int choice, a, b, c;
cout << "1. Add two numbers\n";
cout << "2. Subtract two numbers\n";
cout << "3. Multiply two numbers\n";
cout << "4. Divide two numbers\n\n";
cout << "Enter your selection: ";
cin >> choice;
cout << "Enter first number: ";
cin >> a;
cout << "Enter second number: ";
cin >> b;
if(choice == 1)
c = a + b;
if(choice == 2)
c = a - b;
if(choice == 3)
c = a * b;
if(choice == 4)
c = a / b;
cout << "The result is: " << c << endl;
return 0;
}