Error - ArrayIndexOutOfBounds

**WinDoWLoCuS** · 09-12-2009

Hi
I am trying a program with arrays and I am getting an error. So, I need a little help with arrays. I have posted my code please check it

Code:

public class Array
{
 public static void main(String[] args)throws IOException
 {
  int[] test;
  test=new int[3];
  test[1]=4;
  test[2]=3;
  test[3]=2;
  System.out.println(test[1]);
 }
}

I am getting an error

Code:

 ArrayIndexOutOfBoundsException.

Any help on this or suggestion.

**Modifier** · 09-12-2009

Hi

Code:

test[1]=4;
  test[2]=3;
  test[3]=2;

Arrays start with zero, that is they are zero based. So, your test int[3] array will go from

Code:

test[0]
test[1]
test[2]

If you try to use test[3] you'll go beyond the array's bounds. Please correct that.

**WinDoWLoCuS** · 09-12-2009

Hello

test[0]
test[1]
test[2]

thanks buddy, I did not knew that. After correcting the problem the program works correctly now.

**Praetor** · 09-12-2009

Hi
Arrays ar always zero based. For beginners this concept is confusing, an example is array of three elements have indicies 0,1,2. In your example the array index out of bounds exception occurs because you have written
test[3]=2;
You modified and correct code is here

Code:

public class Array
{
 public static void main(String[] args)throws IOException
 {
  int[] test;
  test=new int[3];
  test[0]=4;
  test[1]=3;
  test[2]=2;
  System.out.println(test[1]);
 }
}