Try the first "[" using instr () result 6. Then print the first 5 characters or "hello", then remove the text of the first 5 characters. text = right (text, len (text) -5) or "[b] [g] as [/g] is [c]?"
now checks the value of the second character (you know the first is a [) if it is a "/" marks the error otherwise you will have the tag open. circles and its closing tag (in this case does not exist) if there is a closing tag (tag = "[/ b]") and dies on the html tag open. redo the procedure and when you try on the close tag (using instr ()) and find it will result in 8. so you have to take the text content between 4 (the first 3 are the opening tag) and 7 (8 starts the closing tag) and printed with html tags. hours to eliminate the print + characters opening and closing tag (respectively 3 and 4) then a total of 11 characters (function right ()). Prints the HTML tag on and take out the 3 characters from the text variable that you have left. Splitting the variable tag and closing tag for each die on the html tag. Finally, the three dots, remove it.
Reply With Quote
)
I would like to suggest you to replace all tags with the relevant html and before inserting the 3 dots fill in all the expected closing tag. Maybe you think this as waste, but try once before ignoring it (might work). Like 
The latter hypothesis that I propose unfortunately does not go in as soon as all the code there are other open tags in bulk and then closing the previous close tags and the structure of the site totally blows. I would choose to follow your earlier suggestion mentioned by "Broot". [INDENT]For that find the last letter contains a check that after the 50 character and put [/ + the last part of the tag open. For example :
Bookmarks