Input and output arguments in java

[Ash maker]

Hello,
I have not much experience with Java, as will show my newbie question, I want to make a method that takes as arguments a number of things, and change. In C++ I spent the arguments References with the "&". I note that the "&" does not exist in Java, or the "inout" style which I used in C++. The arguments are inout they default? Any help on this is highly appreciated. Thanks in advance.

[HardWeaR]

Hello,
You can build a specific object that contains attributes like whatever you want to edit. You can do the get / set methods for these attributes in order to access and modify. But in general, it depends on what you want to conceive. Anyway, if you want to change a parameter of a method, you can do so only if it is an object. You can not change and the reference passed as a parameter of a method.

Public void tri(Object o){
...
o = new Object(); / / Prohibited!
...
}

[Remedy]

Hello,
I think even I have a similar kind of a problem in my code and I have no solution for it, if you can help then it would be great.
This is what I am trying to do.

Public static void hand(String args[]){
...
int temp =0;
Widget = mbid new Bidule();
MyMethod(temp mbid);
...
/ / mbid has been changed without my explicitly specifies
/ / As temp passed by myMethod References rather than copy
 
/ / temp have not been changed! He passed by copy, not References!
}

If you have any solution for this then please help me. Thanks in advance.

[InterNetWorKed]

Hello,
Primitive types are passed by value and objects by reference is as simple as that. If you would like your primitive types are modified, encapsulates in an object (classes Integer, Double, Float, etc.): version 1.5 of java you have the autoboxing which enables you to avoid some cumbersome WRITE. If you need more information on the primitive types in java then you can view the java api on the sun's official site.

[NetworkeR]

Hello,
Just have a look at the following code, this might help you.

Public class MyIntWrapper{
 
	
	private int val;

	Public MyInt(int val){
		this.val = MyValue;
	}
 
	Public int getMyValue(){
		return val;
	}
 
	Public void setMyValue(int val){
		this.val = MyValue;
	}
 
}
 
/ / To declare an instance of that class would be:
	MyIntWrapper wrp = new MyIntWrapper(5);
 
/ / now such a method of any class changing the value of an object MyIntWrapper
 
 
Public 	MyOtherClass{
 
	Public static void addOne(MyIntWrapper wrp){
		wrp.setMyValue(getMyValue()+1)
	}
}
 
/ / example of use
	MyIntWrapper wrp = new MyIntWrapper(5);
MyOtherClass.addOne(Wrapper);
System.out.System.out.println(wrp.getValue); / / returns 6

[SoftWore]

Hello,
Just take a look at the following example, see if this helps you

Public class Wrapper <X>{
 
	
	private X val;

	Public Wrapper(X value){
		this.val = Value;
	}
 
	Public X getValue(){
		return val;
	}
 
	Public X void setValue(X value){
		this.val = Value;
	}
 
}