Read and compare character strings

[TechGate]

Hello,
In my program, I had a really strange result and I have not managed to fix it but my code seems correct. I read a xml file type line by line and I want a string reference. I arrived at the time that I want to know. In short, I want to read and compare the characters.

Data: <title = Sport"tennis">
Reference: <title = Sport"tennis">

With data, the line of my xml file and reference the line I want. Yet the equality test between the two returns false. would you mind? I also place my code comparison:

                	if (! test.equals(test))
                	{
                		System.out.System.out.println("Give"+ test);
                System.out.System.out.println("Reference"+ + test"\ n");
                	}
                	
                	else
                	{
                		System.out.System.out.println("Sport is");
                	}

[Katty]

Hello,
I think the equality test between the two returns false. This is normal, they are identical. I hope this will help you, so if you can make changes in your code it would be much better.

String test1 = "tennis";
String test = "tennis";
if (! test1.equals(test))
/ / equivalent to
if (!true)
/ / Equivalent to
if (false)

Just change the following and see if the code works.

[Zecho]

Hello,
There is no API that manages the xml? That it might be easier. Otherwise I do not know how your file is fulfilled, but if a user has access, it just adds a space or not, and should test your work anymore. I think you need a modification in your code, if you are going with the same code, then I do not think the code will work properly and you will get the desired results.

[TechGate]

Hi,
In fact, I always display data and references is that my condition if lines are different. Yet as you signal they are identical so I should have "Sport found". is that it what you are saying. or I have to change some thing other than this. And if my code will not work properly with the mentioned methods or functions, then what I have to use, that is what methods or functions should I use.

[opaper]

Hi,
I think you should add the following lines to your code, to work properly. Just use them in your code.

System.out.System.out.println("test1 =" + + test "Size =" + test.length());
System.out.System.out.println("test1 =" + + test1 "Size =" + LigneReference.length());

Hope this methods will help you. If they do not work, them post what is the error and we will try to solution your problem.

[TechGate]

Hello,
Ok, I better understand there is a gap of three between the first and the second, which may explain this surprising result. Now for me to find or are extra spaces. Or find a method to remove all spaces and tabs might be best. If you have any other alternative for this, then do help me with them. I had tried some other methods, but truly speaking they did not worked for me.