Java : test a number to find out if its is even or odd

[teenQ]

Hi,

I am learning Java. I want to do a program that can check a number if its odd or even. I have done it with C but now need your help with Java coding.

Thanks for the help in advance.

teenQ

[Matsheet]

Logic:

if (x % 2 == 0) {
  // even 
}

if (x % 2 != 0) {
  // odd
}

... or binary AND operator...

if (( x & 1 ) == 0) {
  // even
}

if (( x & 1 ) != 0) {
  // odd
}

I hope this helps you.

[Grundy]

Check Even-Odd:

 import java.io.*;

public class IfElse{
  public static void main(String[] args) throws IOException{
    try{
      int n;
      BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
      n = Integer.parseInt(in.readLine());
      if (n % 2 == 0)
      {
        System.out.println("Given number is Even.");
      }
      else
      {
        System.out.println("Given number is Odd.");
      }
    }
    catch(NumberFormatException e){
      System.out.println(e.getMessage() + " is not a numeric value.");
      System.exit(0);
    }
  }
}

This is your Java code.

[teenQ]

Hey Thanks for such a prompt reply.

I am running the code right now.

Thanks.

[usterka]

I am in AP Java (high school). I'll show you how I'd check for even or odd!
I do not know how to make that box-within-a-reply, so I'll just enter the program application here:

import java.util.Scanner;
public class EvenOrOdd {
     public static void main(String[] args) {
          Scanner input = new Scanner(System.in);
          int num = 0; 

          System.out.println("Enter a number: ");
          num = input.nextInt();
               
          if (num % 2 == 0) {
               System.out.println("The number you entered is even");
          } else if (num % 2 != 0) {
               System.out.println("The number you entered is odd");
          }
     }
}