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Thread: Array of Strings in C++

  1. #1
    Join Date
    Oct 2008

    Array of Strings in C++

    I'm working on a program in c++, and I've come up against a problem that I can't figure out. I don't imagine that it's too difficult to solve, but it has been giving me trouble.

    What I would like to do is create an array of strings. More specifically, I would like to create an array of char* 's. And the only catch is that I will need to pass the array by reference to several methods. Although from my understanding of pointers, I imagine that this is how things are done inherently in c++.

    I would really appreciate if somebody could give me a snippet of code where an array of char* is declared and assignments are made. I've looked all over, but haven't had any success in finding anything.

  2. #2
    Join Date
    Oct 2008

    Re: Array of Strings in C++

    Are you really sure you want to do that? This would be a lot easier to do with a vector of real honest-to-gosh C++ style strings. Then you don't have to mess with pointers, which are easy to make mistakes with (as I'm sure you're aware )

    #include <iostream>
    #include <string>
    #include <vector>
    using namespace std;
    // pass the vector of strings by reference (note the &)
    // so no copying is needed
    void Display (const vector<string>& v)
    // Vectors "know" how big they are, so you don't have to
    // pass the size separately.
    for (int k = 0; k < v.size(); ++k)
    cout << "String #" << k << ": " << v[k] << endl;
    int main ()
    // Create this vector with a specific size
    vector<string> myStrings(7);
    // Each string automatically expands to accommodate its characters
    myStrings[0] = "Hi";
    myStrings[1] = "I";
    myStrings[2] = "am";
    myStrings[3] = "a";
    myStrings[4] = "vector";
    myStrings[5] = "of";
    myStrings[6] = "strings";
    Display (myStrings);
    // Create this vector with size zero, and let it grow to
    // accommodate the data
    vector<string> moreStrings;
    Display (moreStrings);
    return 0;
    You can use pointers to pass data to functions in C++, but I personally
    prefer to use references, as in the example above.

  3. #3
    Join Date
    Mar 2008

    Re: Array of Strings in C++

    You can do it in the most obvious way. Here is some code:

    void print_strings(const char *arr[], const int arr_sz)
    for (int i=0; i < arr_sz; i++)
    std::cout << arr[i] << std::endl;
    const int arr_sz = 3;
    const char *arr[sz] = { "first", "second", "third" };
    arr[0] = "first modified";
    Is this what you were looking for?

  4. #4
    Join Date
    Jun 2008

    Re: Array of Strings in C++

    No one has given you exactly what you have asked for so here it is, it might
    be what you want, but I doubt it.

    void func(char* (&array)[3]);
    int main()
    char* array[3] = { "apple", "pear", "orange" };
    void func(char* (&array)[3])
    for (int i = 0; i < 3; ++i)
    cout << array[i] << '\n';
    The strange syntax for the parameter of func is how you pass an array by

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