function that takes a 2D array as a parameter

hi,
I defined the following function:

Code:

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p_direction scanning (points position, double heading, int circ [NC] [MC]) (....}

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with

Code:

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struct (int s_point a; y-int);   
  typedef struct s_point * points;
  s_direction struct (double s_ta; double s_dist_obst;);
  typedef struct s_direction * p_direction;

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I use my position as follows:

Code:

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  p_direction d = scan (P1, PI / 2., circ [NC] [MC]);

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but this warning appears: warning: passing argument 3 of 'scan' from incompatible pointer.Why? How do I fix this? Thank you in advance for the answer.

Call it like this:

scanning (p1, PI / 2, circ);

Code:

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p_direction scanning (points position, double heading, int circ [NC] [MC]

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You must send a pointer to a two dimensions to your function.

Code:

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p_direction d = scan (P1, PI / 2., circ [NC] [MC]);

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circ is the pointer, so if you send circ [x] [y] to your function (whatever x and y, since these boxes have been allocated), it retrieves this parameter as a variable int.

Code:

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p_direction d = scan (P1, PI / 2., circ);

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This seems to be better, right?

For a table with n dimensions it is necessary to clarify the last n-1, ie all except the first. Nevertheless it seems to me that the first is optional, ie that its accuracy is left to the programmer.

I specify only the 2nd dimension of the table:

Code:

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  p_direction scanning (points position, double cap, circ int [TM])

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