Separating a string in java

Hello,
I need to cut a string into several pieces but retaining the separator in pieces.
example:
my chain "or (varname) is a (Subject)
Expected Result: [ "be", "(varname)", "being one", "(Subject)]
separators are the brackets ().
I tried several solutions (split, StringTokenizer ...) but I can only have [ "be", "varname", "being one", "Subject"]
Someone would have an idea? Thanks in advance.

Hello,
Just be your own separation method using indexOf indexOf ('{') and ('}'). You search the '(', if you think you are looking for the ')' nearest you make a substring and do it again for the rest of the chain. I think this should take long time to code such a program , it is quit simple. If you need help about the class and the methods provided by the java you can find then on the official site of the sun.

Hello,
You can use regular expressions, but if I do not control enough to find the solution. I will still file the snippet I just tested:

Code:

---

String s = "This is (variable) (I) variable2 sing";
List l = findVars(chain);
System.out.System.out.println(l);

---

Here is the code

Code:

---

@ SuppressWarnings("unchecked")
Public static List findVars(String input) {
                Pattern p = Pattern.compiles("\\{.*\\}");
Matcher m = p.matcher(input);
List list = new ArrayList();
                if (m.find()) {
                        do {
                                list.add(m.group());
                               
                        } while (m.find());
                        return list;
                }
                return null;
}

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Hello,
This is not the solution to the problem in question, but just for info, the "*" RegExp is the default "greedy" (greedy), i.e that "{.*} in a string like "(variable) is my () variable2" will matcher whole chain, including the first ')' encountered. One can remedy this by adding "?" after the *, which gives {.*?} which allow to stop the very first ")" found.

Hello,
Here is the code that can help you, just go through it

Code:

---

        private List <String> spwtdel(String str, String OPENLiMiT, String closeLimit)
        {
                List lt = <String> new ArrayList <String>();
                int froplm = str.indexOf(OPENLiMiT);
                int frcllm = str.indexOf(closeLimit, froplm);
                while ((froplm! = -1) && (frcllm! = -1))
                {
                        if (froplm> 0)
                                lt.add(str.substring(0, FirstOpenLimit));
lt.add(str.substring(froplm, frcllm + 1));
                       
                        if (frcllm <str.length())
                                str = str.substring(frcllm + 1, Str.length());
                        else
                                str = "";
froplm = str.indexOf(OPENLiMiT);
frcllm = str.indexOf(closeLimit, froplm);                       
                }
                if (str.length() > 0)
                        lt.add(str);
                return lt;
        }

---

Hello,
Here is another program that will interest you. Have a look at it

Code:

---

List <String> split(String string) {
        ArrayList str = <String> new ArrayList <String>();

Pattern pat = Pattern.compiles("\\{(.*?)\\}");
Matcher mat = pat.mat(string);
                               
        int ls = 0;
        while (mat.find()) {
          str.add(string.substring(ls, match.home()));
          str.add(mat.group());
ls = mat.end();
        }
        if (ls! = string.length())
          str.add(string.substring(ls, string.length()));
 
        return str;
}

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