How to draw a circle using TI 89

[Bilal]

hi,

I want to ask a simple question about TI 89 (Texas Instruments 89). How can I draw a circle using TI 89. Can anybody please suggest some useful tips regarding this......thanks

[JonathanD]

I think that the scientific calculators are capable of carrying out functions in the form : y = f(x) ...so you need to obtain the explicit form of the function as given in the following form -

(x^2 - 8x) + (y^2 - 12y) = -36

(x^2 - 8x + 10) + (y^2 - 12y + 32) = -36 + 10 + 32

(x-8)^2 + (y-12)^2 = 14

y - 12 = ± square root((14 - (x-8)^2))

y = 12 ± square root((14 - (x-8)^2))

These are the two functions you need to combine to form your circle.

all the best

[Glenny]

Whatever your equation is ? You first need to evaluate that equation in terms of 'Y' and then simply put the appropriate values (normally integers) into the TI 89 application, you 'll get the required result.

[Raine]

Circles are not the functions. You will require the separate conics program to simplify the equation in terms of the required format so that you can easily enter the values.