Output not looping in C++

[Guntoor]

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Hello everyone i have create the DO while looping code but on output this not at all looping, i am always using the do while loop but still i am not able to loop at output. can anyone suggest me what is wrong with my code, here is my code:

    #include <stdio.h>
    #include <conio.h>
     
     
    int main ()
    {
    int numb;
    double chart;
     
    do
    {
    printf ("........");
    printf ("\something 1 numb = 100");
    printf ("\something 2-4 numb = 70");
    printf ("\something 5 numb.... = 50\n");
    scanf ("%d", &numb);
    if(numb==1)
    {
    chart = 100;
    printf ("chart%lf", chart);
    }
    else if((numb<=2)&&(numb>5))
    {
    chart = 100+(numb-1)*70;
    printf("chart : %lf", chart);
     
    }
    else if(numb>=5)
    {
    chart = 100+(numb-3)*70+(numb-4)*50;
    printf ("chart : %lf", chart);
    }
    else
    break;
    }
    while (numb<1);
    getch();
    return 0;
    }

[Jacques25]

On your code the while statement statement loop for one time because you have written code like that. You cant have a value less than or equal to 2 and on the same way greater than 5. Your getting this issue because your while statement not meet the necessary condition and so therefore loop not working on output.

[Author]

i agree with the above reply because below two codes are contradictory:

while(numb < 1)
and
else
break

So i would like to suggest you to change values as said above and also change the while to while(numb > 1) and you don't need the else part if write this code.

[Menominee]

According to me you should have below code:

else if((numb>=2)&&(numb<5))

[Ronchi]

I know above code will solve your issue but for alternative here is another structure for your code and here you don't need to use the do while statement:

    while(1)
    {
    if(...)
    {
     
    }
    else if(...)
    {
     
    }
    else if(...)
    {
     
    }
    else
    break;
    }

[Guntoor]

Everyone thanks for the solution but by looking at above code i just need to ask why we are giving the number 1 on while, can anyone explain me. Here "while(1)"

[Anahera]

If we don't provide some way of getting out of the loop (like break, goto) , the loop will go on forever. The condition tested in a while loop can be any valid C expression. As long as that condition remains true, the while loop will continue. Since 1 is always true, the loop will never end, unless a break statement is reached. Not that while(1) is nothing but an infinite loop which we 'break'. You can create a loop that will never end by using the number 1 for the condition to be tested.