n factorial program in C

[MaryJ]

I've writtin a program in C to calculate the n!(n factorial) but I am obviously doing somthing wrong because I keep getting errors and I think it has something to do with the z=n; and if statements. Please help...


#include<stdio.h>
main()
{

int n; /*n is the number entered by the user*/
int i; /*i is the counter*/

scanf("%d",&n);

printf("Enter a positive integer:\n\n");

z=n; /*z is the result after the first loop is ran*/

for(i=n; i>0; i--)
{
if(n=0)
z=1;

z=z*i;
}

printf("The factorial of %d is:%d",n,z);

}

[GlassFish]

Calculate factorial by using recursion

#include
#include

int ft(int x)
{
if(x==0)
return 1;
else
return x*ft(x-1);
}

void main()
{
int n;
clrscr();
printf("\n Enter a number :");
scanf("%d",&n);
printf("\n Factorial value=%d",ft(n));
getch();
}

[Ucchal]

Here is an simple program that will help you

#include <stdio.h> 
#define VALUE 6 
int y,x; 
void main()  
{    
    x=1;    
    for (y=1; y<=VALUE; y++)      
        x=x*y;    
    printf("The factorial of %d is %d\n",VALUE,x);  
}

[MaryJ]

Is there a way to fix the first one? I need to use a for loop to complete the problem. The if/else is for the condition zero (0).

[Ucchal]

If you are looking for the logic of for loop then here it is

for (y=1; y<=VALUE; y++)      
        x=x*y;

just implement the same in the language you are using.

[MaryJ]

Thanks, that helped. I figured it out