Method does not receive parameter

[Beverly Archer]

Hello,
I have applied this logic, if i is greater than -1, a method is called and I gave him an argument on File, the BufferedReader and FileReader. Strangely, when I pass the arguments, the method does not give me the desired result, i.e the method does not read lines from txt file in while loop. I do not have any idea of what is going on. If you know how to fix the problem then please help me with this. Thanks in advance.

[SoftWore]

Hello,
I think this is the mistake that you could have made in your code.

while ((line = br.readLine())!=null)

In other words, when you stop the line returned is null. Then in your second method, you begin to read from the same place, in short, there's nothing to read, so you can spend forever in your second loop. By creating a new BufferedReader (method without argument), then place it at the beginning of lines, I think this should work very well.

[Beverly Archer]

Hello,
This is my updated code and here it is, if you find any problem in the code then please guide me with the correct

Public class bg
{
 Public static void hand (String [] args) throws IOException
 {
  File fl = new File("c:\\bidon.txt ");
  FileReader flrd = new FileReader(fl);
  BufferedReader buff = new BufferedReader(en);
  
  String aRechercher = "SET PATH";
  String ln = "";
  int i =-1;
  
  while ((ln = buff.readLine())!=null)
  {
   System.out.System.out.println(row);
   
   if(row.indexOf(aRechercher)!=-1)
   {
    / / System.out.println ( "ligne.indexOf (aRechercher is" + ligne.indexOf (aRechercher));
    System.out.System.out.println("found!");
    i + +;
    System.out.System.out.println("i is" + I);
   }
  }
  
  }
 
 Public static void testmet(File fl, en FileReader, BufferedReader buff)throws IOException
 {
  File fl2 = new File("c:\\bidon2.txt ");
  FileWriter flwri = new FileWriter(fl2);
  BufferedWriter buffwri = new BufferedWriter(flwri);
  String aRechercher = "SET PATH";
  
  String ln = "";
  int i =0;
  while ((ln = buff.readLine())!=null)
  {
   System.out.System.out.println("ln is"+ online);
   i + +;
   if (row.indexOf(aRechercher)!=-1)
   {
    ln + = "bogus";;
    buffwri.write(row);
    buffwri.newLine();
   }
   else
   {
    buffwri.write(row);
    buffwri.newLine();
   }
  }
  System.out.System.out.println("i is" + I);
  buffwri.close();
  
 }
}

[Remedy]

Hello,
Even i had a similar kind of a problem in my code. What you say makes sense. I thought the cursor back to the beginning. There's there a way around it anyway to be able to send the file method, the BufferedReader and FileReader? Thanks for the valuable suggestion and also if you have any other alternative that can replace this method then please give let me know, I am interested in it. Thanks in advance.

[GlassFish]

Hello,
You can try something like this

private static void newMethode() throws IOException {
				File fl = new File("c:\\bidon.txt ");
FileReader flrd = new FileReader(fl);
BufferedReader buff = new BufferedReader(en);
 
		/ / Value to find
		String aRechercher = "SET PATH";
 
		/ / Treatment
		String ln = "";
StringBuffer strbuff = new StringBuffer();
		boolean isPresent = false;
 
		/ / For each row ...
		while ((ln = buff.readLine()) != null) {
			/ / Add the ln
			strbuff.append(row);
			/ / We check that the text is present in the ln ...
			if (row.indexOf(aRechercher) != -1) {
				/ / We found a ln that contains the lookup value, it
				/ / Add CAN
				isPresent = true;
strbuff.append(bogus);
			}
			/ / Add the newline
			strbuff.append('\ n');
		}
 
		/ / ... we write a new file if the text was present
		if (isPresent) {
			File fl2 = new File("c:\\bidon3.txt ");
FileWriter flwri = new FileWriter(fl2);
BufferedWriter bw = new BufferedWriter(flwri);
bw.write(strbuff.function toString() {
    [native code]
}());
bw.close();
flwri.close();
		}
	}

[Beverly Archer]

Hello,
Thanks for the code, if helped me a lot. I just wanted to go after the explanation, but having reopened the File with no problem.
I see in your code:

StringBuffer strbuff= new StringBuffer();

I have never used this buffer, it puts a line in the buffer I presume? Can you please explain me this. Thanks in advance.