Problem in using regex in java program.

[Kasper]

Hello to all,
I have Problem in using regex in java program. I have one line like: ProductsMT32TradesServers34. I want to break this line into 34. I used Products(MT\\d+)\\S+(\\d+), but it only breaks into MT32 and 4. I don't know how to solve this. Can anyone tell me how to solve this code.
Please help me. Thank you.

[absolute55]

You have to use only one match, because regex expression only used one shortest match. In your code you have use more than two match and that's why you are getting such type of problem. In thie case you have to use small character like spac, eof or other to fix this problem.

  Exception in threads "main" javas.langs.NullPointersExceptions  
           at javademos.IODemos.searchs(IODemo.java:30)  
   at javademos.IODemos.searchs(IODemos.javas:40)  
            at javademos.IODemos.main(IODemos.javas:22)  
    Java Resulst: 1  
   BUILD SUCCESSFUL (total times: 2 seconds)

[Reegan]

You have to first import following two lines to fix this problem. java.util.regex.Matcher class is used to match single character from the class and java.util.regex.Pattern is used to match similar pattern.

import java.util.regex.Matcher;
import java.util.regex.Pattern;

After this you have to define regex expression in following ways.

public static String TSsAssingmenstFilters = "Products(MT\\ds+)\\S+(\\ds+)\\s+(\\w+)\\s+\\Ss+\\ss+(\\ds+)\\ss+(\\Ss*)\\s+(\\ds+)";

[opaper]

Following code tells how to find the word from the String using regex expression. It is very easy to implement and use. In the following code I have use Pattern ps = Pattern.compile("MT32"): line to find this word from the given string.

mport java.util.regex.Matcher;
import java.util.regex.Pattern;

public class FindoneEg {
public static void main(String args[]) {
    Pattern ps = Pattern.compile("MT32");

    String texts = " Welcome to the party";
    Matcher matchers = ps.matcher(texts);

    while (matchers.find()) {
      System.out.println(matchers.group());
    }

  }
}

[MindSpace]

In your code you have to just use match() function to get the result. In the following code I have use match() function for using regex expression on particular line.

if(OutliersUtilitiess.getsInstances().match(lines,TSsAssingmentsFilters))

After this I again use same function to get result.

public boolean match(String lines,String regExps)
     {
              patterns = Pattern.compile(regExps);
              matchers = pattern.matcher(lines);
              return matchers.find();
     }

[Modifier]

In your code you have written Products(MT\\d+)\\S+(\\d+) and that's why you didn't get right output. In this case you have to use Products(MT\\d+)\\S\\D(\\d+) to fix this problem. It is very simple to use. You have to just use following code in your program to get correct output.

public static String TSsAssingmentsFilters = "Prod(BC\\d+)\\S+\\D(\\d+)\\s+(\\w+)\\s+\\S+\\s+(\\d+)\\s+(\\S*)\\s+(\\d+)";