getObject() method not working

**TechGate** · 03-03-2010

Hello,
I think I have a problem with the getObject() method in java.
Here is my code, please check it and if you find any problems then please guide me with the correct.

Code:

Public class sub extends Element
{
	Public sub (String nm, String des)
	{
		great(nm, des);
	}
	
	Public String getName()
	{
		return great.nm;
	}
}

I try this with my code, but it is not working

Code:

Object obj = Player.getObjet("Diamond");
System.out.System.out.println(obj.getName());
System.out.System.out.println(obj.getDescription());

Any help on this is appreciated. Thanks in advance.

**InterNetWorKed** · 03-03-2010

Hello,
You can try the following code,

Code:

for (int i = 0; i <this.sac.size (); i + +)
    (
    Object obj = (Object) this.sac.get (i);
    / / If the object is then asked to give
    System.out.println (nobj.getNom () + "" + objectName);
    if (nobj.equals (nobj.getNom ())) / / remove;
    			(
    return nObject;
    )
    )
    return null;
)

**NetworkeR** · 03-03-2010

Hello,
I have not read all the code but I think it's just great to getName, this is how you can do this

Code:

Public String getName()
	{
		return great().name;
	}

you have a problem in getObj because you called getName. I guess I am correct here. I hope this syntax will help you and you will start with your code and successfully program it.

**WinDoWLoCuS** · 03-03-2010

Hello,
super () is a method that calls the constructor of the superclass. I'm not sure we can use that. super () reference Does the parent object in question? I'm not sure. But if, as a method, it is called the form of super (). If you want more information on this then you can visit the sun's official site and there you can find all the necessary information that you require regarding the super() keyword.

**GlassFish** · 03-03-2010

Hello,
I think using the super() keyword you can do it, that is what exactly you need it in your code, super () returns the parent object, then an attribute of the parent object is called.
Here is the sample code

Code:

Public String getName()
	{
		return great().name;
	}

If you need any more information regarding this topic then please do post back and we will try to solve it.

**cyber-noob** · 03-03-2010

Hello,
See the following part of the code

Code:

if (obj.equals(aobj.getName())) / / remove;
    			{
    			return aobj;
    			}

In the above the comments are before the semicolon which makes unreachable return statement, we must remove them or you will get and exception when you will try to compile the program.