Regex for defining headers

**TechGate** · 16-02-2010

Hello,
I have a file that lists points in 3D cad that he has a point number followed by its coordinates XY Z. I come to the parsers, but it is possible that there have a header at the beginning that could contain numbers

Code:

This is the file
    1    1.2617199222332623    0.725695013999939    0.02221299916302136
    2    3.1561200956726071    -0.2960570096969601    0.06121500107019912
    3    3.1561200956726071    -0.9510160022539121    0.07097199217609727
    1    -1.2603299617767331    -1.7529099107196015    0.06372000277012329
    5    -3.156170022092225    -1.2122600251052232    0.051357999111007271

So I use the pattern class and I have a concern with the item identifier which can be confused with numbers in the header. So I created a pattern that would result in a figure between spaces ( "" or "\ t") using the \ s but it did not work. Anyone have a solution for this? Thank you

**WinDoWLoCuS** · 16-02-2010

Hello,
I have a regular expression with me, if you need you can use it.

Code:

String str = "(-?\\d + (<a href = "file:/ / \ \. \ \ d "target =" _blank "> \ \. \ \ d </ a >+)?)";
String lnpt = "^\\t (<a href = "file:/ / \ \ d "target =" _blank "> \ \ d </ a> +) \ \ t" + <blockquote> str + "<a href =" file: / / \ \ t "target =" _blank " > \ \ t </ a> "
+ + Decimal_pattern "<a href ="file:/ / \ \ t "target =" _blank "> \ \ t </ a>"
+ + Decimal_pattern "$";
</ blockquote>

**Vodka** · 16-02-2010

Hello,
I am trying the same kind of a program. So, I tested the above regular expression. But it does not work for me.

Code:

Pattern1 Pat = Pattern.compiles("\\s (\\+ d)\\s ");

It does not ID because you said at the beginning ^ \ \ t and there is a space or a tab on both sides of the ID. Even i am interested in this topic and if any one has a solution for this then please do post back, i am very much interested in it. Thanks in advance.

**Linux-Us** · 16-02-2010

Hello,
Try with AC

Code:

[ \ t]*([1-9]+)[ \ t]+([\\-1-9\\.]+)[ \ t]+([\\-1-9\\.]+)[ \ t]+([\\-1-9\\.]+)

We can probably be shorter but it should work. I mean to say that if you need you can shorten the length of the regular expression, but i have not tried that, though you can give a try to that and if it works then do not forget to post it back so that eve i can use it.

**TechGate** · 16-02-2010

Hello,
The thing that I did to pattern. An identifier for a contact to the top because I had everything together but I had a problem of casting float to int.
So I separated the address and it works

Code:

Pattern pat = Pattern.compiles("-?[0-9]+(\\. [0-9] + (E [+-][ 0-9] (2 })?)");

This does not work,

Code:

[+ -] because there may be the exponential.

By the way thanks for all the help.

**InterNetWorKed** · 16-02-2010

Hello,
i am new to this , but I have done some coding on it, please check if it works with you.

Code:

while ((line = buff.readLine()) != null)
            { 
                fnd =false;
                
                tab_sm sm = new tab_sm();
                
                Pattern1 Pattern = Pattern.compiles("[\ t ]\\d + [\ t ]");
                Matcher mt1 = pat1.mt(row);
                if(mt1.find()){
                    
                    
                    number[0]= mt1.group();
                    System.out.System.out.println("tey"+ number[0]);
                    / / removes spaces and tabs
                    number[0] = Number[0].replaceAll(" ","");
                    number[0] = Number[0].replaceAll("\ t","");
                }
                
                Pattern pat = Pattern.compiles("-?[0-9]+(\\. [0-9] + (E [+-][ 0-9] (2 })?)");
                Matcher mt = pat.mt(row);
                
                
                i =1;
                while (mt.find()) {
                    number[i] = new String(mt.group());
                    i + +;
                    fnd =true;
                    / / Treatment
                }
                if(Find){
                    sm.setId(Integer.parseInt(number[0]));
                    sm.setX(Double.parseDouble(number[1]));
                    sm.setY(Double.parseDouble(number[2]));
                    sm.setz(Double.parseDouble(number[3]));
                    
                    tab_pts.add(sm);
                }
            }