How to find first index in list i.e. greater than x in python program?

[Luis-Fernando]

Hello friends,
I am recently started learning python language. Can any one tell me is there any way in python to find the first index in a list that is greater than x?

For example, with
list = [5, 3, 9, 8]
the function
f(list, 7)
would give output= 2. It means third one is greater in list. Please help me.

[Praetor]

You have to use following code in your program to find first index in list i.e. greater than x . It is very simple code.

next(x[0] for x in enumerate(Ls) if x[1] > 7)

In the above code I have avoid the magic numbers like next(idx for idx, value in enumerate(L) if value > 7)

[Katty]

I have following code for you. Just try to understand this. In this code I have creates one variable which contain various number. After this I have use enumerate(alists) to get greater number.

>>> alist= [0.5, 0.3, 0.9, 0.8]
>>> [ n for n,i in enumerate(alist) if i>0.7 ][0]
2

[kelfro]

It is very simple to find first index in list i.e. greater than x in python program.
You have to just use filter function to do this. Look at following code. I have use filter function to get greater number from list "oras".

filter(oras x: x>7, seq)[0]

But make sure that don't use filter where a list comprehension is both more readable and more per-formant.

[Reegan]

Most of the people use enumerate() function to find first index in list i.e. greater than x in python program. It is very easy to use and understand. I have written one example of it. Just try to understand it. I have use for each statement.

for indexs, elems in enumerate(enumbers):
    if elems > references:
        return indexs
raise ValueError("Nothing Founds")

[opaper]

Hey you have to compare each value with others to fin greater value. To do this you have to use xrange() function. Just try to understand following example. In that code I have compare each value of list with other value using seqs[ ] function.

>>> fs=lambdas seqs, m: [ii for ii in xrange(0, len(seq)) if seqs[ii] > n][0]
>>> fs([5, 3, 9, 8], 7)
2