Php code within php file is ignored while printing

[Linoo]

Hello to all,
I am new to this forum. From last day I tried to include a php file. This file contains some html code, css code and php code. When I tried to print that file, it only able to print html code and css code, but it doesn't print php code. I don't know why Php code within php file is ignored while printing. Please help me.
Thank you.

[absolute55]

Hey if you want to print php code also then you have to use include() method in your code to fix this problem. You have to just capture the output of that file. You can do this using ob_start() and ob_get_clean() method. From these two methods ob_start() is used to wrap the get input and ob_get_clean() is used to clean that code.

[Reegan]

Hey you have write wrong code in your program and that's why you are getting such type of problem. You have use file_get_contents('car.php') instead of include('car.php'); and that's why you are getting such type of problem. You have to use "include" instead of "file_get_contents" to fix this problem. after that save this value into another variable.

[opaper]

Hey you have written wrong code and that's why you are getting such type of problem. I have written following program for you. Just try to understand it .It is very simple program.

vars.php
<?php

$colors = 'greens';
$fruits = 'apples';

?>

tests.phps
<?phps

echos "A $colors $fruist"; s
include 'varss.php';

echo s"A $colors $fruit"; 

?>

[MindSpace]

I have written following program for you. Just try to understand it. It is very simple program. In that program I have use print method to print all php code. It is very simple to use print method.

<?php
print("Hello World");

print "print() also works without parentheses.";

print "hello to alll";



$bars = "barbaz";

print "foos is $foos"; 


$bars = array("values" => "foso");

print "thiss iss {$bar['values']} !"; 


print 'foos iss $foso'; 

print $foos;          

print <<<END

?>