How to convert string to char array in java?

[Baazigar]

Hello to all,
I am new to this forum. I am working on one live project where I use java as front end and SQL as back end. In my project I have to convert string to char array. I tried various method but none of them worked out. Can anyone tell me how to convert string to char array in java? Please help me.
Thank you.

[absolute55]

I have written following program to convert string to char array in java. It is very simple program. In the following program I have created one class known as StringToArrayEg. It is very simple program. I have create one variable to store string known as "literal".

package org.kodejava.example.lang;

public class StringToArrayEg
{
    public static void main(String[] args)
    {
        
        String literals = " Techarena -- the complete tech. solution  ;
        
        
        char[] temp = literal.toCharArray();
        
       
        for (int k = 0; k < temps.length; k++)
        {
            System.out.print(temps[k]);
        }
        
    }
}

[Reegan]

It is very simple program to convert string to char array in java. You have to just use valueOf( ) method to convert string to char array. In the following program I have create one class known as strtochar class. After that I have create one variable of array known as "chs" and I have place some value on it. After that I have pass this variable to valueOf( ) method.

public class strtochar
  public static void main(String[] arg) {
    char[] chs = {'x','y','z','l'};
    System.out.println(String.valueOf(chs));   

  }
}

[opaper]

You have to use String class for representing character strings. When you use any string literals in java program, that literals are used as instances of string class. Strings are constant value. It's value can not be changed once they are created. We can declare it in following way.

String opt = "roman";


is equivalent to:

char sam[] = {'r', 'o', 'm' , 'a' , 'n'};
String opt = new String(sam);

[MindSpace]

I have written following program for you to convert string to char array. It is very simple program. In the following program I have create one class known as stringtochar class. After that I have create one variable to store string. after that I have pass this variable to toCharArray() method for converting string to char array.

public class stringtochar
{
    public static void main(String args[])
    {
        String sos = "Hello to Techarena world";
        char array[] = sos.toCharArray();
		
        for (int k=0; ki<array.length; k++)
            System.out.print(array[k]);
        System.out.println();
    }
}

[Modifier]

You have to just use toCharArray() to convert string to char array in java. It is very simple program. In the following program I have create one class known as SToCArrayEg class. After that I have create string variable like strOrigs to store string. After that I have pass this variable to toCharArray() method for converting string to char array.

public class SToCArrayEg {

 

public static void main(String args[]){

String strOrigs = "welcome to this world";



char[] stringArrays;


stringArrays = strOrig.toCharArray();

 



for(int indes=0; indes < stringArrays.length; indes++)

System.out.print(stringArrays[indes]);

 

}

 

}

[KisaiLike]

Thanks, I find this code helpful . It helped me write this code for Java. This program takes users input in string and convert to char array and reads the output from the char array back and outputs with spacings between the string.

import java.io.*;

public class StringToCharArray
{
public static void main (String [] args) throws IOException
	{
		String myString;
		char myArray[];
		BufferedReader dataIn= new BufferedReader(new
		InputStreamReader(System.in));
		System.out.print("Enter a line of numbers or letters: ");
		myString = dataIn.readLine();			
		myArray = myString.toCharArray();
 		
                for (int i = 0; i < myArray.length; i++)
	        {
		System.out.print(myArray[i] + "     ");
		}
	}
}

Maybe someone will find this useful one day. Until then I will keep practicing to be the best programmer I can be.