How to input variable in string.find method in C++

[Caelaan]

I have a c++ program in which i would like to input a variable in string.find as i want to use the same number as the index. Is it possible in C++ and also tell me how to achieve this. Also tell me whether i can set a variable in the find syntax and declare a variable and above all can the string.find() function will be able to read it. Please help me to sort this out.

[Zecho]

You have not posted the code and hence i cannot give you a solution since it is not possible to imagine the whole program and post a code. It would be easier to implement on the problem if you post the code here and also try to explain the program since some of your points are not clear enough and also it does not present a clear picture to your problem.

[Caelaan]

Actually as i was in a hurry hence i could not post the program so i am posting the code here with this reply as you have asked some more information regarding this problem

int main ()
{
string s("aabbccddeeffgghhiijj") ;


string::size_type loc5 = s.find( "dde" , 0 ) ;


cout << loc1 << endl ;

If you see this program you will notice that the input here will be 7 since it continues to start from the starting of the string instead of putting 0 in the above statement can i declare anew variable and will i be able to declare a variable after this will i get that with the string.find() function.please help.

[Katty]

I think you should try this by declaring the index as an int. As far as i know i think that the code should work for sure and hence i have got a solution which should work in your case try the code below

int main ()
{
string s("aabbccddeeffgghhiijj") ;
int pos1 = 5;

string::size_type loc2 = s.find( "dde" , pos1 ) ;
cout << loc1 << endl ;

[Caelaan]

Thanks for the code i have tried the code but it seems that it is not working because i was of the opinion that when i specify the index where to start to search then i will get the result from where it starts off . Consider for example if the index is 5 it will start reading from the alphabet e but the output i get is still from 20.

[Katty]

I thought of a different approach by which i think that you will get this solved if you add on the value in which the position started you might get the solution please consider the code which i have mentioned below:

#include <iostream>
#include <string>

int main()
{
std::string str("aabbccddeeffgg");
size_t pos = 0;


pos1 = str.find('n', 1);
std::cout << pos1 << '\n\n';


pos1 = str.find('n', 0);// start from 0
std::cout << pos1;

std::cin.get();
return 0;
}