Open a file in a jar

[Miles Runner]

Hello everyone,
I am currently developing an eclipse wizard, but my question is a little broader. So my sources are compiled into a wizard.jar, inside of which I have a resources folder, containing a foo.txt. I wish I could read a class file from the jar, but when I read ( "resources / foo.txt"), it does not work. I tried to look on the net an answer to this question, but not found one. Do you know how this can be done. Thank you in advance.

[Xmen]

Hello,
Even I am trying some thing like this. I tried to do this

InputStream foo = getClass().getResource("resources / foo.txt").openStream();

But this did not worked. I am really confused with this concept. So, if you guys can help me it would be great. I have even I have tried some other method and ideas but they did not worked for me.

[Miles Runner]

Hello,
Actually it does not work as I did. The null stream is obtained, probably because he did not find resources / foo.txt ... I'm not sure what path he should put, basically my source is in / src / foo.txt and in / resources /. But I tried to replace ".. / resources / foo.txt", and it does not work better. Any idea about it, how to solve this problem.

[Modifier]

Hello,
I think you should use the following line of code,

InputStream foo = test.class.getResourceAsStream("example" + "foo.txt");

Though I have not tried such example in my code career, but I think this should work for you. I am not saying that the only line will work for you. You have a add some logic to it and then with the logic you have to add this line and try to get the result. Just try it and see if it works.

[Miles Runner]

Hello,
Well I always have the same problem with my code, these are the methods I have tried till now

InputStream t1 = WizardXMLPage.class.getClassLoader().getResourceAsStream("../../ resources / patchs.xsd ");

And this logic

InputStream t1 = WizardXMLPage.class.getClassLoader().getResourceAsStream("/ resources / patchs.xsd");

And this too

InputStream t1 = WizardXMLPage.class.getClassLoader().getResourceAsStream("resources /

Other than these if you have some methods to use or some different logic then please let me know.

[Praetor]

Hello,

InputStream is = getClass().getResourceAsStream("/ resources / foo.txt");

should work if the file foo.txt is in the package resource if you have something like wizard / resources / foo.txt it is necessary that you leave from the wizard. Otherwise tried to put the same package as the class that operates to a simple

InputStream is = getClass().getResourceAsStream("foo.txt");

Try this and if you have any other problem then do post back with the error message , the error message helps us detect exactly what is the error in the code.