Counting file extension

[Vodka]

Hello,
I have a problem and I have no solution for this. I have a folder of data whose relative address is well known for my java application running. And I absolutely have to count the number of files that have a specified extension ex. the *. properties and retrieve all their names without the extension. I do not know how to do it. Can anyone help with this.

[Modifier]

Hello,
I have a code with me, see if this helps you

File fl = new File("Path of directory file properties");
  File[] prls = fl.listFiles(new FileFilter() {
   Public boolean accept(File file) {
    if (file.getName().endsWith(. "properties"))
     return true;
    return false;
   }
  });

[Vodka]

Hello,
This is my program, just have a look at it.

Public class CompteurDeFichiersAvecExtension
{
    Public static void hand(String[] args)
    {
        File fl = new File(. / datas ");
        File[] prls = fl.listFiles(new FileFilter()
                {
                Public boolean accept(File file)
                  {
                  if ((file.isDirectory()==false) &&
                      (file.getName().endsWith(. "properties")))
                         {
                         return true;
                         }
                  return false;
                  }
                });
        for(int i =0; I <prls.length; I + +)
        {
            String = nomAvecExt prls[i].getName();
            int lg = nomAvecExt.length();
            String nm = nomAvecExt.substring(0, Long-11);
            System.out.System.out.println(nm);
        }
    }
}

[Katty]

Hello,
Check out this code, I think it can help you.

Public class CompteurDeFichiersAvecExtensionG
{
    Public static void hand( Final String[] args)
    {
        File fl = null;
        File[] prls = null;
        String fld = null;
        String fil = null;       
        if ( args.length == 0 ) { fld = "."; Filter = ""; }
        else if ( args.length == 1 ) { fld = "."; Filter = args[0]; }
        else { fld = args[0]; Filter = args[1]; }
        
        fl = new File(fld);
        
        if (( ! fil.startsWith(".") )&&( args.length != 0 )) fil = "."+ fil;        

        Final String tmp = fil;
        
        prls = fl.listFiles(new FileFilter()
                {
                Public boolean accept(File file)
                  {
                  if ((file.isDirectory()==false) &&
                      (file.getName().endsWith(tmp)))
                         {
                         / / Only files are made, not
                         / / The directory.
                         return true;
                         }
                  return false;
                  }
                });

        for(int i =0; I <prls.length; I + +)
        {
            String = nomAvecExt prls[i].getName();
            int lg = nomAvecExt.length();
            String nomSansExt = nomAvecExt.substring(0, Long-fil.length());
            System.out.System.out.println(nomSansExt);
        }
        
        System.out.System.out.println("\ n > "+ prls.length+"File *"+ + fil"Found.");
    }
}

[Vodka]

Hello,
I have a small question, How to catch this error if the folder is not referenced.

fl = new File (folder);

NullPointerException in thrown? Yet folder String is never empty. If the program does not find the folder, it crashes. So, I think I should mention a try and catch block in my code.

[Zecho]

Hi,
You can make your code more reliable, by just including the following code.

File fl = new File(. / data ");
if (fl.exists()) {
    doSomething();
} else {
    doNothing();
}

If you have any more problems in this then do post by with your query.