Shell script with sed

[Ameeryan]

Hello
I have an amendment to a file and I do not know how to manage the spaces or tabs in a row
In short: I try to modify a line that would word1 word2 and word3 separated by spaces or tabs to add mot4 him to finish. Any idea how to accomplish it? Thank you in advance.

[kelfro]

Hi

Any idea how to accomplish it?

I think you can use the following line of code to complete you program.

sed-i-e 's / ^ \ (arg1. * arg2 \ ).*$/& 1 ADD / g' file.txt

[Ameeryan]

Hi

sed-i-e 's / ^ \ (arg1. * arg2 \ ).*$/& 1 ADD / g' file.txt

Thanks for the part of the code. But till now I have this with me

sed '/ password / s /.*/& Test' system

I have not really tried you part of code, but I will soon.

[kelfro]

Hello

sed-i-e 's / ^ \ (arg1. * arg2 \ ).*$/& 1 ADD / g' file.txt

1 - / ^ \ (arg1. * arg2 \ ).*$/
- From the beginning of line ^
- I put in a buffer inside the expression contained in parentheses: \ (\). Attention is to precede the brackets \.
- I'll just end of line .* $ (any character repeated zero )

2 - & 1 ADD
- I copy buffer1: & 1
- And add ADD: ADD

when I reread it could even change the order in

sed-i-e 's / ^ \ (arg1. * arg2 .* \) $ / & 1 ADD / g' file.txt

Any more query do post back.

[Ameeryan]

Hi
I want to add the line after the first line that starts with password. I found nothing better than:

sed-i '/ ^ .* password requisite / a \ test' system

I had to add a second word to recognize the line.
We can not well avoid it? for it does not add as many as there is line beginning with password.

[kelfro]

Hello

s / regexp / replacement /

Attempt to match regexp in the workspace. If successful, replace with the replacement part that is. The replacement may contain the special character & to refer to that portion of the workspace that match, and special characters \ 1 through \ 9 to refer to sub expressions, matched with regexp matching.