I am using VBScript for my project and i would like to use VBScript DateDiff function in my code. So it can show amount of time in date, months and also gives the difference between two date-time values. Any help will be extremely appreciated.
I am using VBScript for my project and i would like to use VBScript DateDiff function in my code. So it can show amount of time in date, months and also gives the difference between two date-time values. Any help will be extremely appreciated.
The VBScript DateDiff function is used to determine the amount of time (months, weeks, days, hours, etc.) between two date-time values.This function displays a calendar page of the chosen month and year. In Windows PowerShell you can perform this same kind of date arithmetic using the New-TimeSpan Cmdlet.
In classic ASP, vbscript DateDiff function of date time functions series can also be used to get the number of specified type of time intervals between the two given time values. Returns the number of intervals between two dates. PHP, unfortunately, had no function to perform the same task.
VBScript DatePart Function : the DatePart function to extract the various parts of the original date (no need for the minutes and seconds). The DateAdd function returns a date, it's very useful, allowing you to find out the time intervals between customer dates.
Code:DatePart(interval, date[, firstdayofweek[, firstweekofyear]])
Vbscript DateDiff function returns the number of minutes, seconds, or hours between the specified time values based on time interval. Example : $b = New-TimeSpan $(Get-Date) $(Get-Date -month 12 -day 31 -year 2006 -hour 23 -minute 30)You can use the DateDiff function to find out the specified time intervals between the given two dates. Classic ASP VbScript DateDiff function with Time intervals provides the functionality to get the difference between 2 specified time values.
The following example uses the DateDiff function to display the number of days between a given date and today:
Code:Function DifDate(Date) DifDate = "Days from today: " & DateDiff("a", Now, theDate) End Function
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