Accessing a variable outside a function without arg

[BoanHed]

I have a variable declared in main () and function according to finally use a arg_fonction ():

int main ()
 (
	 int variable = 23;
	 function (& variable);
	
	 getchar ();
	 return 0;
 )
 void function (int * variable)
 (
	 arg_fonction (variable);
 )
arg_fonction void (int * variable)
 (
	 printf ( "% d \ n", * variable);
	 * Variable = 42;
 )

There is no a way to access this variable in another way? Thank you in advance.

[Zecho]

What you want to do is called a global variable, use with moderation ...
To make a global variable, it is sufficient for you to declare it outside your function :

arg_var int = 42;
 int main (void)
 (
      printf ( "% d \ n", arg_var);

      return 0;
 )

[Walby]

Have you tried with varying types of extern?

var j;
$.getJSON("url", function (json) {
// update iji = json.var;
});

[Aberto]

try this example :

main.c

# include <stdio.h>
 # include <stdlib.h>
 # include <string.h>

 # include "global.h"

 int main (void)
 (
     printf ( "foo =% i \ n", foo);
     foo = 2;
     printf ( "foo =% i \ n", foo);

     return 0;
 )

global.h

 # indef global_header
 # define global_header

 # indef GLOBAL_PRIVATE
 extern int foo;
 # else
 int foo = 123;
 # endif

 # endif