Problem in BufferedReader

**SoftWore** · 02-12-2009

Hi
I am very new to java, yesterday I was just trying a program and when I executed the program in my PC it given me a message "cannot resolve symbol" What does this mean? Any I fix the problem easily? Can you guys help me. Thanks in advance. I have posted my code below.

Code:

public class BufferedReader
{
    public static void main (String[]args)
    {
        BufferedReader dtln = new BufferedReader (new InputStreamReader(System.in));
       String no;      
        try
        {
            no = dtln.readLine();
            int nober1 = Integer.parseInt(no);
            no = dtln.readLine();
            int nober2 = integer.parseInt(no);
        }
        
        catch (IOException e)
        {
            System.out.println("Error!");
        }        
        
        int sum = nober1 + nober2;
        System.out.println("The Sum is " +sum);
    }    
}

**Praetor** · 02-12-2009

Hello
Firstly you have named your class BufferedReader, and you are doing a new BufferedReader. So, java is not looking in the BufferedReader default Library but for the constructor in your class. You have to rename the class. Taking about this part of the code.

Code:

public class BufferedReader
{
    public static void main (String[]args)
    {
        BufferedReader dtln = new BufferedReader (new InputStreamReader(System.in));
       String no;      
        try
        {
            no = dtln.readLine();
            int nober1 = Integer.parseInt(no);
            no = dtln.readLine();
            int nober2 = integer.parseInt(no);
        }

The second mistake is that you have defined two integers within a try statement and you are attempting to use them outside the try statement. Due to the scoping laws this can not be possible. So, please change that.

Code:

try
        {
            no = dtln.readLine();
            int nober1 = Integer.parseInt(no);
            no = dtln.readLine();
            int nober2 = integer.parseInt(no);
        }
        
        catch (IOException e)
        {
            System.out.println("Error!");
        }        
        
        int sum = nober1 + nober2;
        System.out.println("The Sum is " +sum);

If you have any more queries do post back.

**SoftWore** · 02-12-2009

Hi
Thanks for your reply. As you said I have changed the class name. Now the problem is with the last two line of the code. I really do not know about this, I am sorry but i ca not even guess what is the error related to. These are the two lines of my code.

Code:

  int sum = number1 + number2;
 System.out.println("The Sum is " +sum);

And the error it displays is

Code:

C:\Documents and Settings\shamed\javaprogs\src\BuffReadwww.java:35: cannot resolve symbol

symbol : variable number1
location: class BuffReadwww
int sum = number1 + number2;

C:\Documents and Settings\shamed\javaprogs\src\BuffReadwww.java:35: cannot resolve symbol

symbol : variable number2

location: class BuffReadwww

int sum = number1 + number2;


The system is out of resources.
Consult the following stack trace for details.
java.lang.OutOfMemoryError

Any help on this. How can I fix this problem and what is this error all about?

**Praetor** · 02-12-2009

Hello
The reason for the program issue is that your variable1 and variable2 are declared inside the try and catch block. That is why, they are not able to reach outside. Just do the following and your code will work.

Code:

try
        {
            no = dtln.readLine();
            int nober1 = Integer.parseInt(no);
            no = dtln.readLine();
            int nober2 = integer.parseInt(no);

            int sum = nober1 + nober2;
            System.out.println("The Sum is " +sum);
        } catch (IOException e) {
            System.out.println("Error!");
        }