Function search in a string

[Amandev]

I have created an algorithm that searches a string in another string, but it does not work.

char * ZString:: search (char * string)
 (
	 int i = 0, j = 0; 
	 bl ok = true;

	 for (i = 0; i <m_long; i + +)
	 (
		 if (m_ch [i] == string [0])
		 (
			 for (int j = 1 j <length (str) & & ok; j + +)
			 (
				 if (m_ch [i + j]! = string [j])
					 ok = false;

				 if (m_ch [i + j]! = string [j] == j & & (length (string) - 1))
					 return & m_ch [i];

			 )

			 ok = true;
		 )
	 )

	 return NULL;
 )

[Zecho]

String to be searched for in the object. The entire content of str must be matched in some part of the string to be considered a match. The Filter function takes a string array and a string containing the search text. It returns a one-dimensional array containing all the elements that match the search text.

[Walby]

I think the error must come from the line 15. You should write:

if (m_ch [i + j] == string [j] == j & & (length (string) - 1))


Otherwise be careful, because when you look at the character [i + j] you might leave the table. To avoid this you must write

for (i = 0; i <(m_long - length (string)); i + +)

for your first loop.

[Aberto]

You must take the first character of your search string in another string. imagined that character is to the number n. So the second you take the character and you compare year + 1, even if it is you did another test with the third character n + 2 and so on until you either \ 0. If you have returned your first character you find in a continuous chain, until you arrive at the end of your search string.