html program to create image flip

[Jalabala]

I have to write the html program for image flip. In am describing what I want to display. I want image to change when cursor is over the picture and when the mouse come out this image, the image flip back.

How can we achieve this output? Please give solution with HTML code.

[Katty]

Hi friend,

I don't no the exact coding but we can create image flip in HTML using Javascript. To achieve this you will have to use event concept. I think something like mouseOver() events may helpful in this.Fire the events code for position of the mouse and the area of the image which you want to flip.

I hope this hints may help you code this program successfully.

[kelfro]

I have successfully run this program to create image flip on my pc. Below is the code for that program

program code:

<SCRIPT language="JavaScript">
<!--

if (document.images)
{
pic1on= new Image(100,25);
pic1on.src="ses2.gif";

pic1off= new Image(100,25);
pic1off.src="ses1.gif";
}

function lightup(imgName)
{
if (document.images)
{
imgOn=eval(imgName + "on.src");
document[imgName].src= imgOn;
}
}

function turnoff(imgName)
{
if (document.images)
{
imgOff=eval(imgName + "off.src");
document[imgName].src= imgOff;
}
}

//-->
</SCRIPT>

Include this coding in the body:

<A HREF="index.html" onMouseover="lightup('pic1')" onMouseout="turnoff('pic1')">
<IMG SRC="http://forums.techarena.in/images/ses1.gif" name="pic1" width="100" height="25" border="0"></A>

[Zecho]

To make image flip program using html use below hints

To change image when mouse is over the image use below code:

function flipon(imgName)
{
if (document.images)
{
imgOn=eval(imgName + "on.src");
document[imgName].src= imgOn;
}
}

To change image when mouse is out of the image area use below code:

function turnoff(imgName)
{
if (document.images)
{
imgOut=eval(imgName + "off.src");
document[imgName].src= imgOut;
}
}