Constant Variables in C++

[Gomeler]

In my code, when I replace the variable in the loop on line 11 by the content (T. Size () - S. Size ()), it no longer works. Yet T. Size () - S. Size () should always give the same thing, so why does not work without intermediate variable? How to change a constant variable in C++?

  # include <iostream>
 # include <stdio.h>
 # include <string>
 # include <vector>

 using namespace std;

 int count (const string & S, const String & T) (
     vector <int> Dp (S. size () + 1, 0); Dp [0] = 1;
 const int T = USELESS. size () - S. size ();
 for (int j = 0, j <= USELESS; j + +)
         for (int i = 0; i <S. size () + + i)
             if (S [i] == T [i + j]) (
                 Dp [i + 1] + = Dp [i];
                 Dp [i + 1]% = 10000;
             )
     return Dp [S. size ()];
 )

 int main () (
     int N; scanf ( "% d \ n", & N);
     for (int x = 1, X <= N, X + +) (
         string T; getline (cin, T);
         printf ( "Case #% d:% 04d \ n", X, count ( "welcome to code", T));
     )
 )

[Zecho]

It is simple in concept, variables declared with ‘const’ added become constants and cannot be altered by the program, There are no 'Constant Variables' in C. A constant [expression] can't be a variable. Its a datum that is not an object. It has no address.

[Aberto]

size_t == unsigned int (or unsigned integer), so the conversion problem can be avoided, an unsigned int is implicitly converted to int if necessary.The error is with your test case 3: T.size () - s.size () = unsigned (+ infinity ), so your program crashes. That's why it is necessary to convert unsigned to signed.

[Walby]

Static const variables cannot be changed. You would normally use them to store hard limits like the maximum length of a file name etc. Why would you want to change the value of a CONSTANT? when is supposed to be constant..... Just declare that variable as an integer or something different than a constant.