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#1
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Loop counting odd and even numbers I want a way (a code in c or c ++) to display the result of given number,The best way to see if a given number is odd or even. Any recommendations and suggestions are appreciated. |
#2
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Re: Loop counting odd and even numbers Code: int main() { int in, evn=0, od=0; do { cout << "Please enter a number:"<< ' '; cin>> input; if ( (evn%2 == 0) && (in >= 0) ) even++; else if (in >= 0) od++; } while (in>=0); cout << "You have entered" << ' '<< od << ' ' <<"odd numbers." << endl; cout << "And" << ' ' << evn << ' ' <<"even numbers." << endl; system("PAUSE"); return 0; } |
#3
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Re: Loop counting odd and even numbers Code: long oddno =1; long maxno; unsigned long lproduct; cout<<"enter the odd number"; cin >> maxno; while( oddno<= maxno ) { long tempno = oddno + 2; lpro = tempno *oddno; cout<<"the product of two numbers first number"<<oddno<<"second number"<<tempno<<"equals"<<lpro<<"\n"; oddno = tempno; } |
#4
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Re: Loop counting odd and even numbers Use the AND operation. Code: for(int i=0;i<=100;i++) { if(i&1) { printf("Odd\n"); } else { printf("Even\n"); } } |
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