How to count numbers from a table in C language

[MKAIF]

I am trying to count values in a table. I read a table with numerical values 1,1,3,1,45,5,12,36,1,2,45,5,5,12,88 etc. by example and I want in my program (C language) count of 1, 3, 5 etc. How can I count these numbers?

[MindSpace]

The problem is that in C we do not necessarily know the length of the table unless it is passed as a parameter to the function. Once you know the length of the table, there is more especially difficulty a counter or table counter, hop on and all that. You do a test when you read a number.

[MKAIF]

I considered this solution but it requires "asking" and test number. I tried this code but I do have a problem with array size. Or 5 files under /tmp, bearing the following names: J0, J1, J2, J3, J4, J5. Each file is written the following values:
18
12

The source code:

#include <stdlib.h> 
#include <stdio.h> 
#define SIZE 4 

int main() 
{ 
int j, cpt, number1, number2; 
int obs; 
int tab[10]; 
char filename[3]; 
FILE *file; 

for(j = 0; j <= SIZE; j++) 
{ 
sprintf(filename,"/tmp/J%d",j); 
if ((file = fopen ( filename, "r" )) == NULL) 
{ 
perror ("Impossible to open the file."); 
} 
else 
{ 
while ( fscanf ( file, "%d %d", &number1, &number2 ) == 2) 
tab[j] = number2; 
printf("tab[%d] = %d\n", j, tab[j]); 
fclose (file); 
} 
} 
printf("Number from? "); 
scanf("%d",&cpt); 

obs = 0; 
for(j = 0; j <= SIZE; j++) 
{ 
printf("tab[%d] = %d\n", j, tab[j]); 
if(tab[j] == cpt) 
{ 
obs = obs + 1; 
} 
} 
printf("Total : %d\n", obs); 
return EXIT_SUCCESS; 
}

The output is:

tab [0] = 12
tab [1] = 12
tab [2] = 12
tab [3] = 12
array [4] = 12
Number from? 12
tab [0] = 877,277,040
tab [1] = 0
tab [2] = 12
tab [3] = 12
array [4] = 12
Total: 3

Why is my picture change?

[MindSpace]

When you have a table, regardless of the language in any loop route table is used myArray.length () or sizeof (myArray).

After we are not obliged to declare a variable that, in general, the compiler is smart enough to avoid a calculation in each loop