#1
 
 
Java math question i need to make a method in which a for loop is used to calculate 2 exponent n. Does anyone know the math formula for mutiplying a number by an inferred exponent? i have this public static void powerOf() { //declare variables int num; int pwr; System.out.println("The powers using a for statement are: "); //for statement for( num = 1; num <11; ++num){ //squaring pwr =(2*num); System.out.println(" 2 to the power of "+ num + " is: " + pwr); } i need it so that when n is instantuated it is a power of 2 lets say soemthing liek 2 power 2 should be 4 and 2 power 3 is 8 etc.. 
#2
 
 
Re: Java math question I don't know about java but have a look at this C example using POW function: Code: /* pow example */ #include <stdio.h> #include <math.h> int main () { printf ("7 ^ 3 = %lf\n", pow (7,3)); printf ("4.73 ^ 12 = %lf\n", pow (4.73,12)); printf ("32.01 ^ 1.54 = %lf\n", pow (32.01,1.54)); return 0; } Code: /* exp example */ #include <stdio.h> #include <math.h> int main () { double param, result; param = 5.0; result = exp (param); printf ("The exponential value of %lf is %lf.\n", param, result ); return 0; } 
#3
 
 
Re: Java math question ty for the reply but i figured it out. public static void exponential() { //declare variables double num; double cons = 2; System.out.println("The powers using a for statement are: "); //for statement for( num = 1; num <11; ++num) { //powering System.out.println(" 2 to the power of "+ num + " is: " + Math.pow(cons, num)); } 

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