#1
 Daren Member Join Date: Feb 2009 Posts: 96
Java math question

i need to make a method in which a for loop is used to calculate 2 exponent n. Does anyone know the math formula for mutiplying a number by an inferred exponent?
i have this
public static void powerOf()
{
//declare variables
int num;
int pwr;
System.out.println("The powers using a for statement are: ");
//for statement
for( num = 1; num <11; ++num){
//squaring
pwr =(2*num);
System.out.println(" 2 to the power of "+ num + " is: " + pwr);

}

i need it so that when n is instantuated it is a power of 2 lets say soemthing liek 2 power 2 should be 4 and 2 power 3 is 8 etc..
#2
 Beans Member Join Date: Aug 2009 Posts: 7
Re: Java math question

I don't know about java but have a look at this C example using POW function:

Code:
```/* pow example */
#include <stdio.h>
#include <math.h>

int main ()
{
printf ("7 ^ 3 = %lf\n", pow (7,3));
printf ("4.73 ^ 12 = %lf\n", pow (4.73,12));
printf ("32.01 ^ 1.54 = %lf\n", pow (32.01,1.54));
return 0;
}```
for exponential function

Code:
```/* exp example */
#include <stdio.h>
#include <math.h>

int main ()
{
double param, result;
param = 5.0;
result = exp (param);
printf ("The exponential value of %lf is %lf.\n", param, result );
return 0;
}```
#3
 Daren Member Join Date: Feb 2009 Posts: 96
Re: Java math question

ty for the reply but i figured it out.

public static void exponential()
{
//declare variables
double num;
double cons = 2;

System.out.println("The powers using a for statement are: ");
//for statement
for( num = 1; num <11; ++num)
{
//powering

System.out.println(" 2 to the power of "+ num + " is: " + Math.pow(cons, num));

}

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