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Thread: Error ASP 0177: 8000401A Server object creation failed

  1. #1
    Join Date
    Apr 2009
    Posts
    67

    Error ASP 0177: 8000401A Server object creation failed

    I need to connect to the Database server, so i created an object that inturn connect to the database and now to access database object i develop the ASP object, whenever i try to connect to the database my ASP page gives the following error message.

    Code:
    Server object error 'ASP 0177: 8000401A' 
    
      Failed Server. CreateObject 
    
      / Raa/adm/RaaReNor03a. Asp, line 111 
    
      The process server did not have been started because the configured identity is incorrect.  Check the username and password.
    Please help how do i get rid of this problem.

    Thanks to those who helps..

  2. #2
    Join Date
    Jan 2006
    Posts
    211

    Re: Error ASP 0177: 8000401A Server object creation failed

    This problem is related to 'Identity' set up for the application which lacks sufficient privileges. This could happen because of several reasons, to check the configuration Open Control Panel -> Administrative Tools-> Component Services-> Expand COM+ Applications-> right-click the application in question-> hit Properties-> and switch to the Identity tab.

    It may also possible that, settings may also automatically identity an application, you simply chose a user that doesn't have access to the DLL, or to a file or system call the DLL touches. There may also a possibility that someone may also changed the Windows password for that user since the application won't automatically adjust for that change.

  3. #3
    Join Date
    Oct 2008
    Posts
    167

    Re: Error ASP 0177: 8000401A Server object creation failed

    Using a connection and recordset objects to access and display your data is fine--ADO will be helpful to design in that way. When you do it using ADO, no instances of Access created on server, and this way work carried well.

    You may create the instance in the following way
    acc = Server.CreateObject("Access.Application")

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