Place a uint > 255 in a buffer

[Elijah]

I am currently working on frames by developing a network driver, so I follow hexa placed in buffers. I would add the size of my package to the frame in my buffer, here's how I proceeded:

UINT size = 4512, // I put a fixed value for my test 
memset (pDest, size, sizeof (size)) // I send this value in my buffer pDest 
//then after I send the frame ...

in hex 4512 = 11A0, or when I do my screen I can see that A0:: a0 a0 a0 a0 ff ff ff ff ff ff 45 75 ...

how do I get for example: 00 00 11 a0 ff ff ff ff ff ff 45 ...

I am not very clear, I hope you see my problem, thank you.

[Lemog]

The memset () that you give the data value (unsigned char) size with sizeof (size) of characters beginning in pDest table.

If you want your chars have different values

pDest [3] = size % 256; 
pDest [2] = (size/256) % 256; 
pDest [1] = (size/256/256) % 256; 
pDest [0] = (size/256/256/256) % 256;

(Assuming pDest is indeed a pointer to unsigned char).

[Ashok.M]

char * pdest = gnigni

* ((UINT *) pdest) = size;
pdest + = sizeof UINT;

by effectively against the endianness depends cpu, so if you want big endian, you fall on the solution Programmer (but with >> and & in principle, or just a >>)

[Elijah]

pDest is PUCHAR type, yes. As against it can not go through having to choose the character of the table? pDest [0], pDest [1 ],... I feel that is what the method of Ashok.M offers but I do not understand how it works?

[Lemog]

When I write C++, I do not write assembler. When I write the assembler, not I do not write C++.

I think this operation has a decomposition as in base 256, so I expressed it as:

size = ((p[0]* 256 + p[1])*256 + p[2])*256 + p[3];