How to rotate a form in c#, or maybe just the controlls?

**maclinux** · 13-01-2009

Hi,

I have a problem. I have a form in c#, with buttons, controlls, textBoxes and others, which I need to rotate 90 degrees. Is this posible in c#?
Can the form be rotated and with it, it's all content, or maybe just the content to be rotated? Buttons, textboxes, checkboxes, labels, can be rotated?
Or maybe this is posible in WPF?

Any ideas?

Thanks!

**Praetor** · 13-01-2009

You can rotate the picture box control by using the following properties.

* Public Property ShowThrough() As Boolean
* Public Property Direction() As DirectionEnum
* Public Property Rotation() As Integer
* Public Property TransparentColor() As Color

ShowThrough will determine whether or not space not used by the image will be transparent and show the control below it. This is accomplished using regions.

Direction as you notice is declared as DirectionEnum. This enumeration was created for the control. It tells the control which way to rotate the image: Clockwise, or Counter_Clockwise.

Rotation is the angle of rotation of the image. It is in degrees. The range is 0 to 359; however, inputting a number outside of the range will scale it to the appropriate angle that is in the range.

TransparentColor will allow you to set a transparent color for the image. The demo project has an image included with a Lime background. If the TransparentColor property is set to Lime - that color in the image will be painted transparent. Unfortunately, it doesn't show the controls below it through, just the parent's background color.

**Ashok.M** · 13-01-2009

It seems very simple, just use the Transform property of your Graphics object with a Matrix object having the appropriate Rotate method called on it.

**Khushal** · 13-01-2009

Well, I don't know about drawing the ellipse or streching and rotating, but I made this code recently to relocate an object. It's
not perfect (the object centre jumps to the mouse position), but it works.

Call this on the MouseMove event of your object:

Code:

if (MouseButtons == MouseButtons.Left)
{
mousePoint = /*Your Form/Groupbox Goes
Here*/.PointToClient(new Point(MousePosition.X - /*Your Control Goes
here*/.Size.Width / 2, MousePosition.Y - /*Your Control Goes
here*/.Size.Height / 2));
/*Your Control Goes here*/.Location = mousePoint;
}

You could fix the above mentioned 'jump to mouse' by recording two offset values on MouseDown, and adding them to the declaration of mousePoint, replacing the (yourControl.Size.Width / 2) and (yourControl.Size.Height /2).

On MouseDown ()
{
xOffset = MousePosition.X - /*Your Control Goes
here*/.Location.X;
yOffset = MousePosition.Y - /*Your Control Goes
here*/.Location.Y;
}

Hope this Helps

**maclinux** · 13-01-2009

Here's the scenario. I have a form, a menu, that is displayed on a regular screen (4:3), but I need to display it on a 16:9 screen, not horizontaly, but rotated 90 degrees, like the screen will be.
Screen rotation, from the display driver/application is not an option.
This is my problem.

**X-Ray** · 13-01-2009

To adjust your screen in C# you have to measure the angles properly while inserting that into your program, it not complicated but if you are newbie to this you just refer to any C# advance book where you will get How to do that but still after that you itself have to implement that in your program and this is little bit lengthy to explain you that problem here.