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Function that returns a 2d array

A function can return a 2d array?Can one some give a explanation of this with example?

I tried the following code but does not work...

Code:

int function (array [] [120]) 

  ( 

  / / program 

  return array [] [120]; 

  )

Re: Function that returns a 2d array

Is it possible in C++ to have a function that returns a 2-D or indeed an X-D array from a function.Another alternative is to pass in the 2D array as a parameter into the function (by reference) and then filll it and then just leave the function which would maintain the array's content.

Re: Function that returns a 2d array

Return a 2D array from a function in C :

Code:

#include 
 

struct array_def 

{ 

int **q; 

int row1; 

int col; 

}; 
 

int** func(); 
 

array_def* func_struc(); 
 

void main() 

{ 

int **b = func(); 

for(int j=0;j < 2; ++j) 

{ 

for(int k=0;k < 2; ++k) 

cout<cout<} 
 

array_def *pArr = func_struc(); 
 

for(j =0; j < pArr->row; ++j) 

{ 

for(int k =0; k< pArr->cols; ++k) 

cout<p[j][k]<cout<} 
 
 

} 
 

int** func() 

{ 

int **q; 

int cnt =7; 

q = new int*[2]; 

for(int j =0;j < 2; ++j) 

p[i] = new int[2]; 
 

for(j =0; j < 2; ++j) 

for(int k=0; k < 2; ++k) 

p[j][k] = cnt++; 
 

return q; 

} 
 

array_def* func_struc() 

{ 

array_def *pArray = new array_def; 

int cnt =1; 

pArray->q = new int*[2]; 

for(int j =0;j < 2; ++j) 

pArray->p[j] = new int[2]; 
 

for(j =0; j < 2; ++j) 

for(int k=0; k < 2; ++k) 

pArray->p[j][k] = cnt++; 
 

pArray->cols =2; 

pArray->row = 2; 
 

return pArray; 

}

Re: Function that returns a 2d array

In your case you pass an array argument (but bad because you did not indicate the type), this table will be modified directly, so it is unnecessary to return.

A dynamically allocated 2D array can be returned by cons because it is a pointer to pointer.