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-   -   Viewing items that are on a table and not in Edi (SQL) (http://forums.techarena.in/software-development/1055240.htm)

beatnik_abx 15-10-2008 07:38 PM
Viewing items that are on a table and not in Edi (SQL)
 
My problem is that I want to do in a function C happens to me an integer less than 100 (ie two digits) to a string of two characters:

23 -> 23
5 -> 05

And more that I try, do not know how to do it. The truth is it was never my strong handling strings with C. So happened to me one way but I have problems with the function and, of course, the handling of characters for the return value, you get part of my code to see if I put help or should I go for another forms.

Code:
char * pasarMinutos (int minutes) (

char length [3]; / * declare string of three characters who will be the maximum * /
int first, second;
length [3] = '\ 0'; / * put the character string at the end of the last position * /
if (minutes> 9) / * if the digit is two numbers * /
(
first = (int) (minutos/10); / * calculate the first number * /
if (first == 1) / * and since I'm going aki putting the first character according to the num * /
(
LENGTH [1] = "1";
)
else if (first == 2)
(
LENGTH [1] = "2";
)
...............................................
else if (first == 9)
(
LENGTH [1] = "9";
)
second = (min-first * 10); / * calculate the second num * /
if (second == 1) / * and the same thing with the first q * /
(
LENGTH [2] = "1";
)
else if (second == 2)
(
LENGTH [2] = "2";
)
......................................
)
else if (second == 9)
(
LENGTH [2] = "9";
)
)
else / * if the number is only one-digit * /
(
LENGTH [1] = "0" / * the first character will be a 0 * /
second = minutes; / * and from aki ago as in the previous * /
if (second == 1)
(
LENGTH [2] = "1";
)
else if (second == 2)
(
LENGTH [2] = "2";
)
....................................
else if (second == 9)
(
LENGTH [2] = "9";
)

)
return length;
);

Katty 15-10-2008 07:41 PM
I am new to this program but I think there's a function in stdlib.h that does that same item ()

Anyway I have been bitten curiosity and I have been thinking about the algorithm. This is what I get:
Code:
itoa2 void (int num, char string []) (

char aux ='0 ';

if (num == 0) (

string [0] = '\ 0';
)
else (

string [0] = (char) (aux + (num% 10));
itoa2 (num / 10, & (string [1]));
)
)
What you think?

Zecho 15-10-2008 07:42 PM
I understand that what you want in this program here:

Code:
int result, value;
char characters [3] = ( "00 "};// this is only for you to put an end to the string

result = valor/10;
characters [0] = result +48 / / 48 is the decimal value of 0 in ascii, 30Hex
resulting value% = 10;
characters [1] = result +48 / / well as the values achieved in ascii


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